Difference between revisions of "Geek Flow Chart Assignment"
From WLCS
Line 17: | Line 17: | ||
Example: | Example: | ||
− | < | + | <syntaxhighlight lang="python"> |
− | + | eat = input("Have you eaten yet today? (y/n)") | |
− | if | + | if eat == "y": |
− | + | print("You ate without me?") | |
− | if | + | if eat == "n": |
− | + | fiveGuys = input("Would you like to get some Five Guys? (y/n)") | |
− | + | if fiveGuys == "y": | |
− | + | print("YES! Five Guys rocks!") | |
− | + | else: | |
− | + | print("WHAT?!? You are crazy! Five Guys rocks!") | |
− | </ | + | </syntaxhighlight> |
Latest revision as of 09:14, 16 September 2014
Objective: Create a program that asks the user various questions that leads them through the
Competencies:
- 043 Design a program using an algorithm, pseudocode, and/or a flowchart.
- 044 Code the program, using a programming language.
- 045 Execute the program with sample data.
- 046 Debug the program.
Procedures:
- Create a python script named geekDating.py
- Ask the user the first question: "Do you have someone in mind? (y/n)"
- Store the user's input into a variable
- If the variable is a "y", then proceed to ask them "Are they available? (y/n)"
- If the variable is a "n", then proceed to "GPF"
- HINT: You will have NESTED if statements as you proceed through the geek dating chart.
Example:
eat = input("Have you eaten yet today? (y/n)")
if eat == "y":
print("You ate without me?")
if eat == "n":
fiveGuys = input("Would you like to get some Five Guys? (y/n)")
if fiveGuys == "y":
print("YES! Five Guys rocks!")
else:
print("WHAT?!? You are crazy! Five Guys rocks!")