Difference between revisions of "Geek Flow Chart Assignment"
From WLCS
Line 18: | Line 18: | ||
<source lang="python"> | <source lang="python"> | ||
− | choice = | + | choice = input("Have you eaten yet today? (y/n)") |
if choice == "y": | if choice == "y": | ||
print "You ate without me?" | print "You ate without me?" | ||
elif choice == "n": | elif choice == "n": | ||
− | choice2 = | + | choice2 = input("Would you like to get some Five Guys? (y/n)") |
if choice2 == "y": | if choice2 == "y": | ||
print "YES! Five Guys rocks!" | print "YES! Five Guys rocks!" |
Revision as of 08:57, 30 September 2011
Objective: Create a program that asks the user various questions that leads them through the
Competencies:
- 043 Design a program using an algorithm, pseudocode, and/or a flowchart.
- 044 Code the program, using a programming language.
- 045 Execute the program with sample data.
- 046 Debug the program.
Procedures:
- Create a python script named geekDating.py
- Ask the user the first question: "Do you have someone in mind? (y/n)"
- Store the user's input into a variable
- If the variable is a "y", then proceed to ask them "Are they available? (y/n)"
- If the variable is a "n", then proceed to "GPF"
- HINT: You will have NESTED if statements as you proceed through the geek dating chart.
Example:
choice = input("Have you eaten yet today? (y/n)")
if choice == "y":
print "You ate without me?"
elif choice == "n":
choice2 = input("Would you like to get some Five Guys? (y/n)")
if choice2 == "y":
print "YES! Five Guys rocks!"
else:
print "WHAT?!? You are crazy! Five Guys rocks!"