Difference between revisions of "Big O Practice Problems"

From WLCS
Line 2: Line 2:
 
* State and explain the Big O complexity for each snippet of code.  Some may require reductions!
 
* State and explain the Big O complexity for each snippet of code.  Some may require reductions!
  
# <source lang="java">
+
1) <source lang="java">
 
//assume myArray contains an array of ints
 
//assume myArray contains an array of ints
 
x = 25;
 
x = 25;

Revision as of 11:02, 6 January 2009

Directions:

  • State and explain the Big O complexity for each snippet of code. Some may require reductions!

1)

//assume myArray contains an array of ints
x = 25;
for (int i = 0; i < myArray.length; i++)
{
	if (myArray[i] == x)
		System.out.println("found!");
}


2)

for (int r = 0; r < 10000; r++) for (int c = 0; c < 10000; c++) if (c % r == 0) System.out.println("blah!");


3)

//assume k is unknown a = 0 for (int i = 0; i < k; i++) { for (int j = 0; j < i; j++) a++; }



4)

int key = 0; //key may be any value int first = 0; int last = intArray.length-1;; int mid = 0; boolean found = false;

while( (!found) && (first <= last) ) { mid = (first + last) / 2;

if(key == intArray[mid]) found = true; if(key < intArray[mid]) last = mid - 1; if(key > intArray[mid]) first = mid + 1; }



5)


int currentMinIndex = 0;

for (int front = 0; front < intArray.length; front++) { currentMinIndex = front;

for (int i = front; i < intArray.length; i++) { if (intArray[i] < intArray[currentMinIndex]) { currentMinIndex = i; } }

int tmp = intArray[front]; intArray[front] = intArray[currentMinIndex]; intArray[currentMinIndex] = tmp; }